Regular expression for validating numbers only

This site uses cookies to deliver our services and to show you relevant ads and job listings.By using our site, you acknowledge that you have read and understand our Cookie Policy, Privacy Policy, and our Terms of Service.A digit in the range 1-9 followed by zero or more other digits then optionally followed by a decimal point followed by at least 1 digit: i.e.this is a digit in the range 1-9 followed by up to 2 other digits then zero or more groups of a full stop followed by 3 digits then optionally your comma and digits as before. anywhere between the digits then try: Actually, none of the given answers are fully cover the request.As written, re Snippet is designed to be dropped into other regular expressions, so you can extract (or avoid) numbers. ' // Optional exponent 0-29 for scientific notation. Despite all the parentheses, it contains no capturing groups. Your use of Stack Overflow’s Products and Services, including the Stack Overflow Network, is subject to these policies and terms.To allow numbers with an optional decimal point followed by digits.

Here are the Jasmine tests, so you can see what it does and doesn't handle: the expression will match arbitrary length strings of digits and 123 will return true. Be aware that technically an empty string is a 0-length string of digits, and so it will return true using ^[0-9]*$ If you want to only accept strings containing 1 or more digits, use instead of * As the many others have pointed out, there are more than a few ways to achieve this, but I felt like it was appropriate to point out that the code in the original question only requires a single additional character to work as intended. '[0-9]' // 1-30 decimal digits of integer or fraction.

Lookbehind has limitations, like the phrase cannot include quantifiers. You can use alternation, but only if all alternatives have the same length.

That's why for some cases I'll be using Lookahead instead, which is the same, but in the opposite way. These flavors evaluate lookbehind by first stepping back through the subject string for as many characters as the lookbehind needs, and then attempting the regex inside the lookbehind from left to right.

I'm sure there's a way to change this behavior, but as I said, I've never really done much with regular expressions.

Example of valid values: "3", "-3", "0", "0.0", "1.0", "0.7", "690.7", "0.0001", "-555", "945465464654" Example of not valid values: "a", "", " ", ".", "-", "001", "00.2", "000.5", ".3", "3.", " -1", "--1", "-.1", "-0", "00099", "099" A number can start with a period (without leading digits(s)), and a number can end with a period (without trailing digits(s)).

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To my knowledge, this matches all the variations on numbers that Java and Java Script will ever throw at you, including "-Infinity", "1e-24" and "Na N".

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